225+144=c^2

Solution for 225+144=c^2 equation:

225+144=c^2

We move all terms to the left:

225+144-(c^2)=0

We add all the numbers together, and all the variables

-1c^2+369=0

a = -1; b = 0; c = +369;
Δ = b2-4ac
Δ = 02-4·(-1)·369
Δ = 1476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1476}=\sqrt{36*41}=\sqrt{36}*\sqrt{41}=6\sqrt{41}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{41}}{2*-1}=\frac{0-6\sqrt{41}}{-2}
=-\frac{6\sqrt{41}}{-2}
=-\frac{3\sqrt{41}}{-1}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{41}}{2*-1}=\frac{0+6\sqrt{41}}{-2}
=\frac{6\sqrt{41}}{-2}
=\frac{3\sqrt{41}}{-1}
$